O Level MathematicsE2.13 Linear programming (interpret inequalities to define a region).

📐 Shading Success: Mastering Linear Programming Regions!

Edudent Academy
25 Dec 25

Linear programming questions frequently appear in the O-Level Paper 2, and they usually carry a healthy number of marks. **Being able to translate a worded constraint into an inequality and then shade the correct region on a graph is essential** because every optimisation question starts with this skill. If the feasible region is wrong, the final answer will be wrong too!

What is a Feasible Region?

In linear programming, we want to find values of xx and yy that satisfy a set of linear inequalities at the same time. **All such points form the *feasible region*.** Interpreting a single inequality is easy; the challenge is combining several of them on one set of axes without mixing up which part to shade. Remember: • **Solid line** for \le or \ge (point *on* the line is included). • **Dashed line** for << or >> (point on the line is *not* included).

  • Always rearrange each inequality into the form ymx+cy \ge mx + c or ymx+cy \le mx + c before drawing, unless it is a vertical line.
  • Test a simple point, usually (0,0)(0,0), to decide which half-plane to shade.
  • Label the **feasible region** clearly; examiners often award a mark just for a neat, correctly-shaded diagram.

Worked Example: Smoothie Stand Profit

Problem: A school fair sells two types of smoothies—Berry (xx cups) and Tropical (yy cups). Each Berry smoothie needs 200ml200\,\text{ml} of juice and 11 scoop of yoghurt. Each Tropical needs 150ml150\,\text{ml} of juice and 22 scoops of yoghurt. The stall has 6000ml6000\,\text{ml} of juice and 6060 scoops of yoghurt. Write the inequalities that define the feasible region and sketch it. Solution (step-by-step): 1. Juice constraint:
200x+150y6000200x + 150y \le 6000
which simplifies to
4x+3y1204x + 3y \le 120
. 2. Yoghurt constraint:
1x+2y601x + 2y \le 60
. 3. Non-negativity:
x0,  y0x \ge 0,\; y \ge 0
. 4. Draw the lines 4x+3y=1204x + 3y = 120 and x+2y=60x + 2y = 60 on the same axes, using solid lines because of \le. 5. For each line, test (0,0)(0,0): it satisfies both inequalities, so shade the region **towards** the origin for each half-plane. 6. The intersection of all shaded areas (including the first quadrant) is the **feasible region**. Mark it clearly and label the corner points for later optimisation.

By practising the translation from words to inequalities and careful shading, you build a rock-solid foundation for every linear programming question. **Grab graph paper, invent scenarios, and keep drawing those regions**—accuracy comes with repetition, and so do marks!