O Level MathematicsE5.3 Volume and surface area (pyramids, cones, spheres, and composite solids).

πŸ“ Solid Secrets Unlocked! Mastering Volume & Surface Area

Edudent Academy
15 Jan 26

Understanding how to calculate volume and surface area is **crucial** for succeeding in O-Level exams. From designing water tanks to estimating ice-cream scoops, these skills connect classroom maths to real-world situations.

Key Formulas and Concepts

For every solid, remember that **volume measures the space inside** while **surface area measures the external skin**. For example, a cone’s volume is V=13Ο€r2hV=\frac{1}{3}\pi r^2 h and its curved surface area is A=Ο€rlA=\pi r l, where ll is the slant height.

  • Pyramid: V=13(baseΒ area)Γ—heightV=\dfrac{1}{3}(\text{base area})\times\text{height}
  • Sphere: V=43Ο€r3V=\dfrac{4}{3}\pi r^3, A=4Ο€r2A=4\pi r^2

Worked Example: Ice-Cream Cone with Hemispherical Scoop

Problem: A cone of radius 4 cm4\,\text{cm} and height 10 cm10\,\text{cm} is topped with a hemisphere of the same radius. Find the total volume of the composite solid, leaving Ο€\pi in your answer until the final step.

  • Step 1:
    Vcone=13Ο€r2h=13Ο€(4)2(10)=1603π cm3V_{\text{cone}}=\frac{1}{3}\pi r^2 h=\frac{1}{3}\pi(4)^2(10)=\frac{160}{3}\pi\,\text{cm}^3
  • Step 2:
    Vhemisphere=23Ο€r3=23Ο€(4)3=1283π cm3V_{\text{hemisphere}}=\frac{2}{3}\pi r^3=\frac{2}{3}\pi(4)^3=\frac{128}{3}\pi\,\text{cm}^3
  • Step 3:
    Vtotal=Vcone+Vhemisphere=1603Ο€+1283Ο€=96π cm3β‰ˆ301.6 cm3V_{\text{total}}=V_{\text{cone}}+V_{\text{hemisphere}}=\frac{160}{3}\pi+\frac{128}{3}\pi=96\pi\,\text{cm}^3\approx301.6\,\text{cm}^3

Practice combining these formulas with care, and you’ll handle any composite solid the exam throws at you. **Keep practising** to build confidence!